![I don't understand this explanation for \sum_(n=0)^\infty((-1)^n)/(5n-1)? Why test for convergence/divergence AGAIN, if the Limit Comparison Test confirms that both series are the same? | Socratic I don't understand this explanation for \sum_(n=0)^\infty((-1)^n)/(5n-1)? Why test for convergence/divergence AGAIN, if the Limit Comparison Test confirms that both series are the same? | Socratic](https://useruploads.socratic.org/IJNGAZ1qQGmjuJYFPCa5_lateximg.png)
I don't understand this explanation for \sum_(n=0)^\infty((-1)^n)/(5n-1)? Why test for convergence/divergence AGAIN, if the Limit Comparison Test confirms that both series are the same? | Socratic
Determine the series is absolutely convergent or conditionally convergent or divergent ? | Physics Forums
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real analysis - Every non absolutely convergent series can be rearranged to converge to any $\lim \sup / \inf$ (Rudin) - Mathematics Stack Exchange
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![The comparison tests Theorem Suppose that and are series with positive terms, then (i) If is convergent and for all n, then is also convergent. (ii) If. - ppt download The comparison tests Theorem Suppose that and are series with positive terms, then (i) If is convergent and for all n, then is also convergent. (ii) If. - ppt download](https://images.slideplayer.com/25/8059767/slides/slide_8.jpg)
The comparison tests Theorem Suppose that and are series with positive terms, then (i) If is convergent and for all n, then is also convergent. (ii) If. - ppt download
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LESSON 65 – Alternating Series and Absolute Convergence & Conditional Convergence HL Math –Santowski. - ppt download
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How to Obtain the Sum of an Absolutely Convergent Series by Regrouping or Rearranging the Terms of the Series | Calculus | Study.com
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